Question

What is the perimeter of rectangle WXYZ, with vertices W(-3,7), X(-5,4), Y(1,0), and Z(3,3) to the nearest unit. 20,237 results

Answer 1

Use the distance formula to find width and length D= sqrt[(x2−x1)^2+(y2−y1)^2], then use the perimeter formula, P=2width+2length

Answer 2

The perimeter of rectangle WXYZ is
`6√(13)\approx 21.633`

Explanation:

A rectangle WXYZ, with vertices W(-3,7), X(-5,4), Y(1,0), and Z(3,3).

Distance formula:
`d=√((x_2-x_1)^2+(y_2-y_1)^2)`

Using distance formula to find length of each side of rectangle.

Length of Side WX

`WX=√((-3+5)^2+(7-4)^2)=√(13)`

Length of Side XY

`WX=√((1+5)^2+(0-4)^2)=2√(13)`

Length of Side YZ

`WX=√((3-1)^2+(3-0)^2)=√(13)`

Length of Side WZ

`WX=√((3+3)^2+(7-4)^2)=2√(13)`

Perimeter of rectangle = 2(L+B)

`B=WX=YZ=√(13)`

`L=XY=WZ=2√(13)`

`P=2(√(13)+2√(13))`

`P=6√(13)`

Hence, The perimeter of rectangle WXYZ is
`6√(13)\approx 21.633`