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Engineers must consider the breadths of male heads when designing helmets. The company researchers have determined that the population of potential clientele have head breadths that are normally distributed with a mean of 6.9-in and a standard deviation of 0.8-in.In what range would you expect to find the middle 98% of most head breadths?Between and .If you were to draw samples of size 47 from this population, in what range would you expect to find the middle 98% of most averages for the breadths of male heads in the sample?Between and

User Simon Linder
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The population of potential clientele have head breadths normally distributed with mean 6.9 in and standard deviation 0.8 in

98% of the breadths must differ from the mean by no more than 2.33 times the standard deviation.

This mean the the range we would expect to find the middle 98% of most head breadths is represented by the interval [6.9 - 2.33*0.8, 6.9 + 2.33*0.8] = [5.04, 8.76] in

If we are considering samples of size 47, the standard deviation for the mean of each sample is given by:


\frac{\sigma}{\sqrt[]{n}}=\frac{0.8}{\sqrt[]{47}}=0.117\text{ in}

In this case, we would expect to find 98% of most averages for the breadths of male heads in the interval [6.9 - 2.33*0.117, 6.9 + 2.33*0.117] = [6.63, 7.17] in

User Aadmaa
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