117k views
0 votes
If the area of a square is 38 less than 2 times the area of a hexagon, and the sum of the areas of the square and hexagon is 46, what are the areas of the square and hexagon?

2 Answers

3 votes
hexagon is 8 and the square is 24
User Basse Nord
by
8.9k points
6 votes

\bf \begin{cases} s=\textit{area of the square}\\ h=\textit{area of the hexagon} \end{cases} \\\\\\ \textit{38 less than 2 times the area of a hexagon}\implies \boxed{s}=2h-38 \\\\\\ \textit{we also know that their sum is }\implies s+h=46 \\\\\\ \boxed{2h-38}+h=46\implies 3h=46+38\implies 3h=84 \\\\\\ h=\cfrac{84}{3}\implies h=28

what's the area of the square? well, s = 2h - 38.
User TrustworthySystems
by
7.8k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories