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Solve cos x + sq. root of 2 = - cos x for x over the interval {0,2pi].

A) x = 3pi/4
B) x = 3pi/4 + 2npi
C) x = 3pi/4 and 5pi/4
D) x = pi/4 and 7pi/4

User Andrian
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2 Answers

6 votes

Answer:

C. X = 3pi/4 and 5pi/4

Explanation:

this is the correct answer for this question

User Jasonfungsing
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7.2k points
3 votes

see attached picture for the answer:

I have fixed the answer


Solve cos x + sq. root of 2 = - cos x for x over the interval {0,2pi]. A) x = 3pi-example-1
User Alexandre TRINDADE
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7.6k points