Solve cos x + sq. root of 2 = - cos x for x over the interval {0,2pi]. A) x = 3pi/4 B) x = 3pi/4 + 2npi C) x = 3pi/4 and 5pi/4 D) x = pi/4 and 7pi/4 - QAmmunity.org

Solve cos x + sq. root of 2 = - cos x for x over the interval {0,2pi]. A) x = 3pi/4 B) x = 3pi/4 + 2npi C) x = 3pi/4 and 5pi/4 D) x = pi/4 and 7pi/4

asked Nov 8, 2018 116k views

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