Question

What is the 32nd term of the arithmetic sequence where a1 = −34 and a9 = −122? (1 point)

Answer 1

-375

Explanation:

Answer 2

The 32nd term of the arithmetic sequence is -386.

Explanation:

Given: The arithmetic sequence where
`a_1=-34` and
`a_9=-122`

We have to find the 32nd term of the arithmetic sequence.

Consider the given sequence with
`a_1=-34` and
`a_9=-122`

We know , For a given sequence in an Arithmetic sequence with first term
`a_1` and common difference d , we have,

`a_n=a_1+(n-1)d`

We first find the common difference "d".

`a_9=-122`

`a_9=a_1+(9-1)d`

`a_1=-34` , we have,

`-122=-34+8d`

Solve for d , we have,

-88= 8d

d = - 11

Thus, 32nd term is
`a_(32)=a_1+(32-1)d`

`a_(32)=-34+32\cdot (-11)`

`a_(32)=-386`

Thus, The 32nd term of the arithmetic sequence is -386.