Question

We want to fill a basin 3m wide, 5m long and 1m deep using atap with a flow rate of 2m^3 / h.1 °) How long does it take to fill the basin?2 °) Express the flow rate of the tap in L / min. We will round to the hundredth.

Answer 1

Part 1

First we have to find the volume of the basin. We must multiply the dimensions to do so.

V= (3)(5)(1) m^3

V= 15 m^3

If the tap has a flow of 2 m^3 per hour it means that it would take 7.5 hours to fill the basin. ( Dividing 15 m^3 by 2 m^3/h)

The answer of the first part is 7.5 hours.

Part 2

To express the flow rate in L/min we would have to multiply 2m^3 by 1000 ( Since 1000 L= 1 m^3) and then divide the result by 60 minutes ( Since 1 hour has 60 minutes). Doing so, we have:

`2(m^3)/(h)\cdot\frac{1000\text{ L}}{1m^3}\cdot\frac{1h}{60\text{ min}}=33.33\text{ L/min}`

The answer of part 2 is 33.33 L/min (Rounding to the hundredth).