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Find a 2 × 2 matrix b ≠ o and b ≠ i2 such that ab = ba, where a = 1 7 0 1 . b =

User Snukus
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1 Answer

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If
\mathbf A is invertible, then we can simply choose
\mathbf B=\mathbf A^(-1) because for any invertible matrix
\mathbf X by definition we must have
\mathbf{XX}^(-1)=\mathbf X^(-1)\mathbf X=\mathbf I.

We have
\det\mathbf A\\eq0, as


\det\mathbf A=\begin{vmatrix}1&7\\0&1\end{vmatrix}=1*1-0*7=1

which means
\mathbf A is non-singular and has an inverse. The inverse itself would be


\mathbf A^(-1)=\frac1{\det\mathbf A}\begin{bmatrix}1&0\\-7&1\end{bmatrix}^\top=\begin{bmatrix}1&-7\\0&1\end{bmatrix}
User Bradgonesurfing
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