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6(x+1)-__(8x+5)= -26x-14Fill in the blank

User Logar
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1 Answer

15 votes
15 votes

Given the equation below:

Let the blank be the letter y.


6\left(x+1\right)-_{}y(8x+5)_{}=-26x-14

We are required to fill in the blank to make the equation true.

We can re-write the equation as:


\begin{gathered} 6x+6-8xy-5y_{}=-26x-14 \\ (6x-8xy)+(6-5y)=-26x-14 \end{gathered}

Comparing the left-hand side and right-hand side of the equation: (Taking coefficients of x), we have:


\begin{gathered} 6x-8xy=-26x \\ -8xy=-26x-6x \\ -8xy=-32x \\ \text{Divide both sides by -8x} \\ y=4 \end{gathered}

Therefore, we can fill the blank with the number 4.

Thus:


6\left(x+1\right)-_{}4(8x+5)_{}=-26x-14

User Johnson Abraham
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