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The area of a rectangle is 452in2452⁢in2. if the width of the rectangle is xx inches, write a function for the perimeter, p(x)p(x) .
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The area of a rectangle is 452in2452⁢in2. if the width of the rectangle is xx inches, write a function for the perimeter, p(x)p(x) .

User Swagatika
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Length L of the rectangle = 452/x inches where x is the width.

Perimeter p(x) = 2 (L +x) = 2 (452/x + x)

= 2 ( 452 + x^2) / x answer
User Robyn Paxton
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