Question

1.674 x 10^–24 g of neutrons is how many atomic mass units (amu)?

Answer 1

Answer : The atomic mass in
`1.674* 10^(-24)g` of neutrons are, 1.008 amu.

Explanation :

1 mole of substance always contains
`6.022* 10^(23)` number of atoms. The mass of one moles of any substance is equal to the atomic mass unit.

As we know that,

1 gram =
`6.022* 10^(23)amu`

As we are given that:

Mass of neutrons =
`1.674* 10^(-24)g`

Now we have to determine the number of atomic mass unit.

As, 1 gram =
`6.022* 10^(23)amu`

So,
`1.674* 10^(-24)g` =
`(1.674* 10^(-24)g)/(1g)* (6.022* 10^(23)amu)`

= 1.008 amu

Therefore, the atomic mass in
`1.674* 10^(-24)g` of neutrons are, 1.008 amu.