Question

Lola rode her bike for 7/10 of an hour on Saturday and 3/5 of an hour on Sunday. How much longer did she ride her bike on Saturday than Sunday?

Answer 1

1 hr = 10/10
1/10 of an hr= 6 min
(7)(6)=42
Saturday she rode her bike for 42 min
Sunday
1 hr = 5/5
1/5 of an hr = 12 min
(3)(12)= 36
On sunday she rode her bike for 36 min
Finally
42-36= 6
She rode her bike 6 min longer on saturday than sunday

Answer 2

Answer:Lola ride for
`(1)/(10)` of an hour extra on Saturday as compared to Sunday

Explanation:

Given: Lola rode her bike for
`(7)/(10)` of an hour on saturday

and for
`(3)/(5)` of an hour on sunday

Therefore difference of the two rides time

⇒
`(7)/(10)`-
`(3)/(5)`

Multiplying and dividing
`(3)/(5)  by 2`

⇒
`(7)/(10) -(6)/(10)`

⇒
`(1)/(10)` of an hour