Question

Which describes a trains acceleration if it changes speed from 25 M/s to 10 m/s in 240s

Answer 1

25 - 10 = 15

The train has slowed down by 15 M/s in a period of 240s, therefore;
15/240 = 0.0625 M/S²

Thus the train has decelerated by 0.0625 M/S² (metres per second, per second).

Hope this helps! :)

Answer 2

Answer: The acceleration of the train will be
`-0.0625m/s^2`

Explanation:

Acceleration is defined as the rate of change of velocity of an object.

Mathematically,

`a=(\Delta v)/(t)`

where,

a = acceleration

`\Delta v=v_2-v_1` = Change in velocity

t = Time

We are Given:

`a=?m/s^2\\v_1=25m/s\\v_2=10m/s\\t=240s`

Putting values in above equation, we get:

`a=((10-25)m/s)/(240s)=-0.0625m/s^2`

Negative sign implies this is the negative acceleration.

Hence, the acceleration of the train is
`-0.0625m/s^2`