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The quotient of

y^2-16 ..... y+4
--------- / ------------
4y-16 ....... 16y

User Chunkyguy
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1 Answer

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\displaystyle{ (y^2-16)/(4y-16) / (y+4)/(16y)= (y^2-16)/(4y-16)\cdot(16y)/(y+4)\\\\


\displaystyle{ = (y^2-4^2)/(4(y-4)) \cdot(16y)/(y+4)= ((y-4)(y+4))/(4(y-4))\cdot(16y)/(y+4) = (16y)/(4)=4y


Answer: 4y


Remark:
y^2-4^2=(y-4)(y+4) by the difference of squares identity, or formula.
User Auralbee
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