Question

A capacitor has plates of area8.89 x 10-4 m2. To create acapacitance of 1.11 x 10-8 F, howfar apart should the plates be?[?][?] × 10¹²¹ m

Answer 1

The capacitance of a capacitor is calculated based on 3 values, area of plates, distance between them and epsilon zero, which is the electric permitivity at vacum.

`\begin{gathered} C=(A)/(d)\cdot\xi0 \\ 1.11\cdot10^(-8)F=(8.89\cdot10^(-4)m^2)/(d)\cdot8.854188\cdot10^(-12)F/m \\ d=7.091\cdot10^(-7)m \end{gathered}`