How many gold atoms would have to be lined up to span 4.5 mm ?

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asked Nov 3, 2018 18.9k views

1 Answer

Denis Ivin · Answer 1 · 2018-11-06T22:02:09+0000

1×10⁻¹⁰m is an Angstrom and diameter of gold is 2.70 Angstroms
4.45 mm = 0.00445m
(2.7 x 10¹⁰) a = 4.45 x 10⁻³
a = (4.45 x 10⁻³) / (2.7 x 10⁻¹⁰)
=16481481.48 gold atoms

How many gold atoms would have to be lined up to span 4.5 mm ?

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