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4x^2-x-5 form and factorization

User Thiaguerd
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1 Answer

17 votes
17 votes

Solution

Factorise the equation


4x^2-x-5

Step 1: Break the expression into groups


\begin{gathered} 4x^2-x-5 \\ 4x^2+4x-5x-5 \end{gathered}

Step 2: factorise the expression


\begin{gathered} 4x^2+4x-5x-5 \\ 4x(x+1)-5(x+1) \\ (x+1)(4x-5) \end{gathered}

Therefore the answer is


(x+1)(4x-5)

User Himel Nag Rana
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