Question

1. What is the vertex of y-3=-(x+2)^2

A. (3,-2)
B. (2,-3)
C. (-2,3)
D. (-3,2)

2. What are the x-intercepts for the graph of y=3(x-2)(x+6)?
A) (-2,0) and (6,0)
B) (0,-1) and (0,6)
C) (0,1) and (0,-6)
D) (2,0) and (-6,0)

3. What is the vertex of the graph of this function ? y=-(x-1)(x+3)
A. (-1,4)
B. (2,5)
C. (1,-3)
D. (-2,-3)

4. The point (1,0) lies on the graph of the function y=2x^2-x-6.
True
False

Answer 1

For #2, you need a value of x that will make y = 0. This is because the x-intercept is the value of x where the line crosses the x-axis.