Differentiate the ff y=(2x+5)^2 (x-4)

McNets asked Apr 5, 2023

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McNets asked Apr 5, 2023

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15 votes

Solution

We have the following expression:

We can use the product rule and we have the following:

$y^(\prime)=2(2x+5)\cdot2\cdot(x-4)+(2x+5)^2\cdot(1)$

Then we can simplify and we have:

$y^(\prime)=(8x+20)(x-4)+(2x+5)^2=8x^2-32x+20x-80+4x^2+20x+25$

If we simplify we got:

$y^(\prime)=12x^2+8x-55$

Tirso answered Apr 12, 2023

by Tirso

2.5k points

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