FOIL
F = first
O = order
I = inner
L = last
(x - 3)(4x + 2)
F = x(4x)
O = 2(x)
I = (-3)(4x)
L = (-3)(2)
= F + O + I + L
Therefore,
x(4x) + 2(x) + (-3)(4x) + (-3)(2)
1.6m questions
2.0m answers