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Factor 18v⁹+33v⁸+14v⁷ completely ​

User Imagist
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1 Answer

1 vote

Answer:


v^(7) x (6v+7) x (3v+2)

Explanation:

18v^9 + 33v^8 +14v^7

Factor out v^7 from the expression

v^7 x (18v^2+33v+14)

write 33v as a sum

v^7 x (18v^2+21v+12v+14) *like this 21v+12v

Factor out 3v from the expression

v^7 x (3v x (6v+7)+12v+14)

Factor out 2 from the expression

c^7 x (3v x (6v+7)+2(6v+7)

Factor out 6v+7 from the expression

v^7 x (6v+7) x (3v+2)

User Kolby
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