184k views
5 votes
If a cylinder has r= 10 inches and a volume of 6283 cubic inches to the nearest cubic inch what is the height of the cylinder to the nearest inch

User Annika
by
7.9k points

2 Answers

3 votes
The height of the cylinder round to the nearest cubic inch is 10 inches
User Marcus Rossel
by
7.3k points
2 votes

Answer:

20 inches.

Explanation:

We have been given that the radius of a cylinder is 10 inches and volume is 6283 cubic inches. We are asked to find the height of the cylinder to the nearest inch.


\text{Volume of cylinder}=\pi r^2h


\text{6283 inch}^3=\pi (10\text{ inch})^2h

Switch sides:


\pi (10\text{ inch})^2h=\text{6283 inch}^3


100\pi\text{ inch}^2h=\text{6283 inch}^3


\frac{100\pi\text{ inch}^2h}{100\pi\text{ inch}^2}=\frac{\text{6283 inch}^3}{100\pi\text{ inch}^2}


h=19.999410\text{ inches}


h\approx 20\text{ inches}

Therefore, the height of the cylinder is approximately 20 inches.

User Kasun Kariyawasam
by
8.7k points

Related questions

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.