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If a cylinder has r= 10 inches and a volume of 6283 cubic inches to the nearest cubic inch what is the height of the cylinder to the nearest inch

User Annika
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2 Answers

3 votes
The height of the cylinder round to the nearest cubic inch is 10 inches
User Marcus Rossel
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2 votes

Answer:

20 inches.

Explanation:

We have been given that the radius of a cylinder is 10 inches and volume is 6283 cubic inches. We are asked to find the height of the cylinder to the nearest inch.


\text{Volume of cylinder}=\pi r^2h


\text{6283 inch}^3=\pi (10\text{ inch})^2h

Switch sides:


\pi (10\text{ inch})^2h=\text{6283 inch}^3


100\pi\text{ inch}^2h=\text{6283 inch}^3


\frac{100\pi\text{ inch}^2h}{100\pi\text{ inch}^2}=\frac{\text{6283 inch}^3}{100\pi\text{ inch}^2}


h=19.999410\text{ inches}


h\approx 20\text{ inches}

Therefore, the height of the cylinder is approximately 20 inches.

User Kasun Kariyawasam
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