Question

The molar mass of magnesium (Mg) is 24.30 g/mol. There are 6.02 mc022-1.jpg 1023 atoms in 1 mol. How many atoms are present in 48.60 g of Mg?

Answer 1

48.60g Mg x (1 mol Mg /24.3g Mg) x (6.02x10^23) = 1.20x10^24

Answer 2

Answer:
`1.204* 10^(24) atoms` of magnesium are present 48.60 grams of magnesium.

Step-by-step explanation:

Molar mass of the magnesium = 24.30 g/mol

Given mass of the magnesium = 48.60 g

`moles=\frac{\text{Given mass}}{\text{molar mass}}`

Moles of magnesium =
`(48.60 g)/(24.30 g/mol)=2 mol`

`1 mol=6.02* 10^(23) atoms`

Number of a magnesium atoms in 2 moles:

`2* 6.02* 10^(23)=1.204* 10^(24) atoms`

`1.204* 10^(24) atoms` of magnesium are present 48.60 grams of magnesium.