Question

1.)A rectangle has an area of 72 square centimeters and the length is twice the width. The perimeter of the rectangle

2.)If sides of a square are increased by 4 cm, the area is increased by 40 cm^2. Find the length of a side of the original square.

The topic is System of linear equations with two variables

please give me the solution

Answer 1

1.

area = L x w = 72

L = 2w

72 = 2w*w = 2w^2

divide by 2

36 = w^2

w = sqrt(36) = 6

l = 2*6 =12

perimeter = 2L +2W = 2*12 + 2*6 = 24+12 = 36

2.

sqrt(40)= 6.324555 cm ( round to 6.32 )

6.32 - 4 = 2.32 cm original length of a side