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Calculate the rate constant for the first-order decay of 24na (t1/2 = 14.7 h).

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This problem is pretty straight forward since we are given the half time and we simply have to find for the rate constant. The equation relating the two variable is:

t1/2 = ln(2) / k

where k is the rate constant, therefore:

k = ln(2) / t1/2

k = ln(2) / 14.7 h

k = 0.047 / hour

User Phinze
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