Question

A snowmobile has an initial velocity of 3.0 m/s. if it accelerates at the rate of 0.50 m/s squared for 7.0 seconds, what will its final velocity be?

Answer 1

It's final velocity would be +6.5 m/s. You would use the kinematic equation:
Vf = Vi + at, then plug in the numbers. Vf = 3 + (.5 x 7). .5 x 7= 3.5, then adding it to Vi, which is 3, would get you Vf = 6.5

Answer 2

6.5m/s

Step-by-step explanation:

Acceleration is defined as the change in velocity of a body in a specific time interval. Mathematically,

Acceleration = Change in velocity/time where;

Change in velocity = final velocity (v) - initial velocity (u)

Acceleration (a)= final velocity (v) - initial velocity (u)/time (t)

a = v-u/t

Given a = 0.50m/s²

u = 3.0m/s

v = ?

t = 7.0secs

Substituting the given datas i n the formula for acceleration gives;

0.50 = v-3/7

0.5 × 7 = v-3

3.5 = v-3

v = 3.5+3

v = 6.5m/s

Therefore the final velocity of the snowmobile will be 6.5m/s