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Find the sum of an 8-term geometric sequence when the first term is 7 and the last term is 114,688 and select the correct answer below.

2 Answers

5 votes
It is multiplied by 4 each time.
User Andrew Swann
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6 votes
first term a1 = 7
8th term a1*r^7 = 114688

so r^7 = 114688/7 = 16384

r = 16384 ^ (1/7) = 4

S8 = a1 * (r^n - 1 )/ (r - 1) = 7 * (4^8 - 1) / 3 = 152,915 answer
User Archer
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9.0k points