Question

Avery gets newsletters by email . he get one for sports every 5 days, one for model rail rounds every 10 days , and one for music every 8 days. If he got all three today how many more days will it be until he gets all three newsletters on the same day again?

Answer 1

To find when they all meet, we have to find the lowest common multiple (LCM). To do that, we can do a bit of guess and check where we find the multiples of the highest number and see if they're multiples of the other 2. Since 10 is a multiple of 5, we know all multiples of 10 are multiples of 5, so we just have to find when 10 and 8 meet. 10*1=10, which doesn't work. 10*2=20, which doesn't work. Neither does 30, but for 40, 8*5=40 and 10*4=40, proving that all 3 are together every 40 days

Answer 2

The answer is 40 days.

Explanation:

Avery gets newsletters as one for sports every 5 days, one for model rail rounds every 10 days , and one for music every 8 days.

To find when Avery will get all three mails of sports,model rail rounds and music again, we will find the least common factor of 5, 10 and 8.

5 = 5

10 = 2 x 5

8 = 2 x 2 x 2

LCM = 5 x 2 x 2 x 2 = 40

Hence, after 40 day Avery will get all the three mails again on same day.