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Limit as x approaches 0 of (tan7x)/(sin3x)

User Kaddath
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so... using L'Hopital rule, LH, since this one is a indeterminate type


\bf \lim\limits_(x\to 0)~\cfrac{tan(7x)}{sin(3x)}\implies \underline{LH}\quad \lim\limits_(x\to 0)~\cfrac{7sec^2(7x)}{cos(3x)}\implies \cfrac{7\cdot (1)/(cos^2(7x))}{cos(3x)} \\\\\\ \lim\limits_(x\to 0)~\cfrac{7\cdot (1)/(cos^2(0))}{cos(0)}\implies \cfrac{7\cdot (1)/(1)}{1}\implies 7
User Jose Selesan
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