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DE bisects AB at C. If AC =8x-23 and CB=3x+22 Find X

User Scorpio
by
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2 Answers

7 votes
8x-23=3x+22
subtract 3x
5x-23=22
add 23
5x=45
divide 5
x=9
User Jauboux
by
7.7k points
4 votes

Answer:

x = 9.

Explanation:

Given : DE bisects AB at C. If AC =8x-23 and CB=3x+22.

To find : Find X.

Solution : We have given DE bisects AB at C.

Bisector : A point which cut the line in to two equal parts.

A_____C_____B

AC = CB . ( C bisect AB)

Plug the values.

8x - 23 = 3x + 23 .

On subtracting both sides by 3x

8x - 23 - 3x = 22 .

5x - 23 = 22 .

On adding both sides by 23 .

5x = 23 +22 .

5x = 45 .

On dividing both sides by 5 .

x = 9.

Therefore, x = 9.

User Ajb
by
8.1k points