Question

there was a total of $548 collected for the school play. the adult tickets cost $6 and the student tickets cost $4. if 12 more student tickets were sold than adult tickets, find the number of adult and student tickets sold.

Answer 1

You can first make the equations:

6x+4y=548
y-12=x

Here, you can use the substitution method and you get:

6(y-12)+4y=548
6y-72+4y=548
10y=620
y=62

Then there are 62 student tickets and 50 adult tickets.

Answer 2

Answer: There are 50 adult tickets and 62 student tickets.

Explanation:

Since we have given that

Cost of adult ticket = $ 6

Cost of student ticket = $ 4

Total cost = $ 548

Number of adult ticket be 'x'.

Number of student ticket be 'x+12'

According to question, we get that,

6x+4(x+12)= 548

6x+4x+48 = 548

10x = 548-48

10 x = 500

x = 500 ÷ 10

x = 50

x + 12 = 50 + 12 = 62

Hence, there are 50 adult tickets and 62 student tickets.