Question

A cellular telephone transmits electromagnetic waves at a frequency of 835 mhz. what is the wavelength of these waves?

Answer 1

The wavelength of electromagnetic waves transmitted by a cellular phone at 835 MHz is approximately 0.36 meters, calculated using the formula λ = c / f.

Step-by-step explanation:

The frequency of electromagnetic waves transmitted by a cellular phone and the wavelength of those waves are inversely related according to the formula λ = c / f, where λ is the wavelength, c is the speed of light (approximately 3 × 108 m/s), and f is the frequency of the wave.

For cellular telephone signals at a frequency of 835 MHz (which is 835 × 106 Hz), the wavelength can be calculated as follows:

1. Convert the frequency to hertz: 835 MHz = 835 × 106 Hz.
2. Use the formula λ = c / f, where c is the speed of light (3 × 108 m/s) and f is the frequency.
3. Calculate the wavelength: λ = 3 × 108 m/s / 835 × 106 Hz = 3 × 108 / 835 × 106 = 0.35928 meters.

Therefore, the wavelength of the electromagnetic waves transmitted at a frequency of 835 MHz is approximately 0.36 meters (or 36 centimeters).

Answer 2

HI!

instead of just giving you the answer, i will help you to understand it in simple terms.

As electromagnetic waves (read: light) move forwards it 'vibrates' up and down. The frequency of light tells us how many up-down vibrations it makes each second (1hz = 1 up-down vibration per second & 1mhz = 1 million up-down vibrations per second). Each individual vibration is called one wave.

Since we also know how many meters light travels in 1 second (290,000,000 meters), we can easily see that (in the case of this specific question) every '290,000,000' meters, there are '835,000,000' vibrations or waves.

It's then just a simple division to work out what is the length of just one wave! - which is what we call the wavelength of light at that frequency.

290,000,000 / 835,000,000 = 0.34m (or 34cm)