Question

Tv screens are measured on the diagonal. if we have a tv-cabinet that is 64 inches long and 52 inches high, how large a tv could we put in the space (leave 2-inches on all sides for the edging of the tv)

Answer 1

Basically, we are to find the area of the television screen. Because a TV is rectangular in form, the formula for the area is written below:

A = L×W

The given dimensions are 64 inches in length and 52 inches in width. But that includes the edges. To compute for the screen area only, we subtract 4 inches (2 inches on both sides) to each dimension.

A = (64 - 2)(52 - 2)
A = 3,100 square inches

Answer 2

76.84 inches.

Explanation:

We have been given that a TV -cabinet is 64 inches long and 52 inches high.

After leaving 2 inches on all sides, our new dimensions would be:

Length:
`64-2-2=64-4=60`

Height:
`52-2-2=52-4=48`

Now, we need to find diagonal of the television using Pythagoras theorem.

`\text{Diagonal}^2=60^2+48^2`

`\text{Diagonal}^2=3600+2304`

`\text{Diagonal}^2=5904`

Take square root of both sides:

`\text{Diagonal}=√(5904)`

`\text{Diagonal}=76.83749`

`\text{Diagonal}\approx 76.84`

Therefore, we could put a 76.84 inches TV.