Question

Question 2 (1 point)What is the slope of any line perpendicular to the line 8x +9y =3 in the standard (x,y) coordinate plane?

Answer 1

To lines are perpendicular when the product of their slopes is equal to -1.

Then, m1*m2 = -1

Now, we need to find the slope of any line perpendicular to the line 8x+9y=3

First, get the slope-intercept form y=mx+b

Solve for y:

8x+9y=3

9y=-8x+3

y= -8x/9 + 3/9

The slope m1 = -8x/9

Then,

(-8x/9)m2 = -1

Solve for m2:

-8*m2 = -1*9

-8*m2 = 9

m2 = -9/-8

m2 = 9/8

Hence, the correct answer is option a.