Question

A. Looking at the diagram above, what is the net force in the horizontal direction?

b. What is the net force in the vertical direction?

Answer 1

A) Net force in the horizontal direction is 19.641 N

B) Net force in the vertical direction is 20 N

Step-by-step explanation:

The normal force (20 N) and the weight force (20 N) cancel out.

Next lets find the horizontal and vertical components on the right side of the diagram.

We are given the angle and the hypotenuse.

First lets find the opposite side (vertical component).

`sin(x)(O)/(H)`

`O=Hsin(x)`

`O=40sin(30)`

`O=20`

Now lets find the adjacent side (horizontal component).

`cos(x)=(A)/(H)`

`A=Hcos(x)`

`A=40cos(30)`

`A=34.641`

Now we can ignore the 40 N force.

We are left with 1 force in the vertical direction.

So the net force in the vertical direction is 20 N

We are left with 2 forces in the horizontal direction.

We have 1 force of 15 Newtons moving in the left direction.

We also another force of 34.641 Newtons moving to the right.

So the net force in the horizontal direction is 19.641 N.