What is the equation of the line that passes through the points 1 1/2 and (-1,-1)

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$\bf \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ % (a,b) &({{ 1}}\quad ,&{{ (1)/(2)}})\quad % (c,d) &({{ -1}}\quad ,&{{ -1}}) \end{array} \\\\\\ % slope = m slope = {{ m}}= \cfrac{rise}{run} \implies \cfrac{{{ y_2}}-{{ y_1}}}{{{ x_2}}-{{ x_1}}}\implies \cfrac{-1-(1)/(2)}{-1-1}\implies \cfrac{(-3)/(2)}{-2} \\\\\\ \cfrac{(-3)/(2)}{(-2)/(1)}\implies \cfrac{-3}{2}\cdot \cfrac{1}{-2}\implies \cfrac{3}{4}$

$\bf y-{{ y_1}}={{ m}}(x-{{ x_1}})\implies y-\cfrac{1}{2}=\cfrac{3}{4}(x-1)\\ \left. \qquad \right. \uparrow\\ \textit{point-slope form} \\\\\\ y-\cfrac{1}{2}=\cfrac{3}{4}x-\cfrac{3}{4}\implies y=\cfrac{3}{4}x-\cfrac{3}{4}+\cfrac{1}{2}\implies y=\cfrac{3}{4}x-\cfrac{1}{4}$

What is the equation of the line that passes through the points 1 1/2 and (-1,-1)

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