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How many mol of table salt (NaCl) are in a 238 g box? 4.07 x 100 mol NaCl 9.74 x 10–23 mol NaCl 1.39 x 104 mol NaCl 2.04 x 100 mol NaCl

2 Answers

7 votes

Answer:

A = 4.07 mol NaCl

Step-by-step explanation:

I just took the test and got it right

User ElenaHristova
by
8.4k points
0 votes
1 mole of NaCl is 58.37 g

so its 238/59 = 4.07

Its A
User Stephan Palmer
by
7.5k points

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