Question

Consider the balanced chemical equation,

MgCl2(aq) + 2AgF(aq) → 2AgCl(s) + MgF2(aq)


If both reactants are completely consumed and we produce 20 formula units of AgCl, how many ions of Mg and F did we start with?

A) 10 ions of Mg and 20 ions of F

B) 10 ions of Mg and 10 ions of F

C) 20 ions of Mg and 10 ions of F

D) 20 ions of Mg and 20 ions of F

Answer 1

10 ions of Mg and 20 ions of F

Step-by-step explanation:

In the balanced equation, one ion of Mg ends up reacting with 2 fluoride ions.The ratio 1:2 matches ups with 10 Mg to 20 F.

Answer 2

The number of ions of Mg and F that started is

10 ions of Mg and 20 ions of F ( answer A)

Explanation

MgCl2 (aq) + 2 AgF(aq) → 2AgCl(s) + MgF2 (aq)

from equation above the mole ratio of MgCl2 :AgCl is 1 :2 therefore the number of Mg ions = 20 x 1 /2 = 10 ions

The mole ratio of AgF: AgCl is 2:2 therefore the number of F ions

=20 ion x2/2 = 20 ions