Question

Consider a triangle with vertices at S(-2,-3), A(2,3), and N(5,-4).

Part A: What is the shortest side of the triangle? Select the correct response.

A. Line SA
B. Line AN
C. Line NS
D. All sides are congruent.

Part B: Justify your answer from part A.

Answer 1

the answer is A because the distance between it is shorter than the distance between+3 and -4

Answer 2

Explanation:

Given that a triangle has vertices S(-2,-3), A(2,3), and N(5,-4)

To find side lengths we can use distance formula between two vertices

SA =
`√((2+2)^2+(3+3)^2) =√(52)`

AN=
`√((5-2)^2+(-4-3)^2) \\=√(58)`

NS
`√((5+2)^2+(-4+3)^2) \\=√(50)`

Thus comparing we find that side NS is the shortest side

Option C is right answer