Question

John has a bag of marbles that contains 12 red marbles 20 green Marbles and 17 blue marbles if John pulls one marble out of the bag what is the probability that it will not be red? That is P (not red)?

What is the probability that He will draw a purple marble? That is P (purple)?

Answer 1

Sample space ={12 R, 20 G, 17 B} = 49 possible outcomes

P(RED) = 12/49 = 0.2449
P(NOT RED) = 1 - 0.2449 = 0.755

P(Purple) = 0/49 =0 ((Not Possible)

Answer 2

`P(not~red) = \displaystyle(37)/(49)`

`P(Purple) = 0`

Explanation:

We are given that the bag contains 12 red marbles, 20 green marbles and 17 blue marbles.

Total number of marbles = 12 + 20 + 17 = 49

Formula:

`Probability = \displaystyle\frac{\text{Number of favourable outcomes}}{\text{Total number of outcomes}}`

We have to find probability of not drawing a red marble from the bag.

First we will evaluate P(red)

`P(red) = \displaystyle(12)/(49)`

Thus,

`P(not~red) = 1 - P(red) = 1 - \displaystyle(12)/(49) = \displaystyle(37)/(49)`

`P(Purple) = \displaystyle(0)/(49) = 0`

Because there are no purple marble in the bag.