Question

Suppose a treadmill has an average acceleration of .0050 m/s2. How much does it's speed changer after 4.8 minutes?

Answer 1

This one is nice and straight forward :)

simply calculate how many seconds are in 4.8 minutes like this:
4.8min x 60s = 288s

Then to find the ∆v (∆v = symbol for change in velocity) multiply the acceleration 0.0050m/s^2 by 288s
∆v = 1.44m/s



0.0050m/s
`x^(2)`