Question

How many molecules are present in 936 g of glucose (C6H12O6)? (The molar mass of glucose = 180.16 g/mol.)

Answer 1

Number of moles glucose:

936 / 180.16 = 5.1953 moles

1 mole --------------- 6.02 x 10²³ molecules
5.1953 moles ----- ?

= 5.1953 * 6.02 x 10²³ / 1

= 3.1275 x 10²⁴ molecules

hope this helps!

Answer 2

Answer: The number of molecules present in given amount of glucose are
`31.28429* 10^(23)`

Step-by-step explanation:

To calculate the number of moles, we use the equation:

`\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}`

We are given:

Mass of glucose = 936 g

Molar mass of glucose = 180.16 g/mol

Putting values in above equation, we get:

`\text{Moles of glucose}=(936g)/(180.16g/mol)=5.195mol`

Now, according to the mole concept:

1 mole of a compound contains
`6.022* 10^(23)` number of molecules.

So, 5.19 moles of a compound will contain
`5.195* 6.022* 10^(23)=31.28429* 10^(23)` number of molecules.

Hence, the number of molecules present in given amount of glucose are
`31.28429* 10^(23)`