Question

I need help with my math

Answer 1

Question:

Write each of the following equations in y = mx + b form

Solution:

1) Let the equation

`2y=\text{ -1x-8}`

Dividing both sides of the equation by two, we have that this is equivalent to:

`y\text{ = }(-1)/(2)x-(8)/(2)`

this is equivalent to:

`y\text{ = }(-1)/(2)x-4`

Then the above equation is in the form y = mx +b.

2) Consider the following equation:

`y-4\text{ = -3(x-3)}`

adding to both sides of the equation the number 4, we get:

`y\text{ = -3(x-3) + 4}`

now, using the distributive property, we get:

`y\text{ = -3x+9 + 4}`

this is equivalent to:

`y\text{ = -3x +13}`

Then the above equation is in the form y = mx +b.

3) Let the following equation:

`0.2x\text{ + 0.3y = 0.5}`

subtracting to both sides of the equation the term 0.2x , we get:

`\text{ 0.3y = 0.5}-0.2x`

this is equivalent to:

`\text{ 0.3y = }-0.2x+0.5`

now, dividing both sides of the equation by 0.3, we have that this is equivalent to:

`\text{ y = }(-0.2)/(0.3)x+(0.5)/(0.3)`

this is equivalent to:

`\text{ y = }(-2)/(3)x+(5)/(3)`

Then the above equation is in the form y = mx +b.

4) Consider the following equation:

`(1)/(4)y+3\text{ = -5x}`

subtracting to both sides of the equation the number 3 , we get:

`(1)/(4)y\text{ = -5x}-3`

now, multiplying both sides of the equation by 4, we get:

`y\text{ = -20x-12}`

Then the above equation is in the form y = mx +b.