Question

While on the moon, an astronaut experience the different gravity. If an astronautjumped up with a speed of 2.2 m/s to a height of 1.2 m, what amount of gravitationalacceleration did he experience?

Answer 1

v^2 = u^2 - 2gs

Where:

V = final velocity

g = gravity

u= initial velocity

s= height

At s max, V =0

0^2 = 2.2^2 - 2 g 1.2

2 g 1.2 = 4.84

2.4 g = 4.84

g= 4.84/2.4

g= 2.01 m/s^2