Question

A gram of gasoline produces 45.0kj of energy when burned. gasoline has a density of 0.77/gml . how would you calculate the amount of energy produced by burning 48.l of gasoline?

Answer 1

To find the amount of energy produced by burning 48.1 liters of gasoline, convert liters to milliliters, calculate the mass using the density, and multiply by the energy density to get 1666.665 MJ.

Step-by-step explanation:

To calculate the amount of energy produced by burning 48.1 liters of gasoline, we first need to convert the volume of gasoline to mass using the provided density, and then multiply the mass by the energy produced per gram. Since the density of gasoline is given as 0.77 g/mL, we first convert liters to milliliters:

48.1 L × 1000 mL/L = 48100 mL

We then calculate the mass: 48100 mL × 0.77 g/mL = 37037 g (or 37.037 kg) of gasoline. Next, we use the provided energy density: 45.0 kJ per gram to find the total energy output:

37037 g × 45.0 kJ/g = 1666665 kJ or 1666.665 MJ

Therefore, 48.1 liters of gasoline would produce 1666.665 MJ of energy when burned.

Answer 2

Given that there is 48 liters of gasoline to be burned and that 45 kJ of energy is released per gram of gasoline burned, the amount of energy that the gasoline fuel produces can then be calculated, First, we convert 48 liters of gasoline to units of mass (grams) in order to use the given conversion of 45 kJ per gram of gasoline. To do this, we use the density of gasoline which is 0.77 g/mL. The following expression is then used:

48 L gasoline x 1000 mL/L x 0.77 g/mL x 45 kJ/g gasoline = 1663200 kJ

The amount of energy produced by burning 48 L of gasoline was then determined to be 1663200 kJ.