Question

HELP PLEASE,

Part a of the question was posted earlier on.

Answer 1

`\bf \lim\limits_(x\to 6)~\cfrac{x^2+x+42}{x-6}\implies \lim\limits_(x\to 6)~\cfrac{(x+7)(x-6)}{(x-6)}\implies \lim\limits_(x\to 6)~x+7 \\\\\\ \lim\limits_(x\to 6)~(6)+7=13 \\\\\\ \textit{since the original equation holds for all, }x\\e 6,\textit{ then it approaches}\\ \textit{the same limit as }x+7`