Question

If a game consists of picking a number from a bag of beans numbered 2, 3, 3, 4 and 5 and flipping a coin, which probabilities are equivalent?I. P(3 and tallII. P(even bad head)III. P(odd and head)A) I and IIB) I and IIIC) II and IIID) none of the above

Answer 1

Step 1:

Draw a table to illustrate the information

Step 2:

`\text{Probability of any event = }\frac{Number\text{ of required outcomes}}{\text{Number of possible outcomes}}`

Step 3:

Total possible outcomes = 10

I) P( 3 and Tail )

Number of required outcomes = 2

`P(3\text{ and tail ) = }(2)/(10)\text{ = }(1)/(5)`

II)

P( even and head)

Number of required outcomes = (2H, 4H) = 2

`P\text{ ( even and head) = }(2)/(10)\text{ = }(1)/(5)`

III)

P( odd and head)

Number of required outcomes = (3T, 3T, 5T) = 3

`P(\text{odd and head) = }(3)/(10)`

Final answer

Option A I and II have equivalent probabilities