Question

Square EFGH stretches vertically by a factor of 2.5 to create square E′F′G′H′. The square stretches with respect to the x-axis. If point H is located at (-2, 0), what are the coordinates of H′ ?

Answer 1

Since it is stretched vertically, the transformation is
(x,y) -> (x, ky) where k is the vertical scale factor = 2.5

If H(-2,0), then H' = (-2,0)->(-2,2.5*0)=(-2,0)

Answer 2

Explanation:

Alright, lets get started.

The square is stretched vertically.

The scale factor is given as 2.5 = k

The point H is changes to H'

The given H is :
`(-2, 0)`

The new stretched H' will be :
`(-2, k *0)`

because k is the scale factor

So, new H' point will be :
`(-2, 2.5*0) = (-2, 0)`

means the co-ordinates of H' is (-2,0) : Answer

Hope it will help :)