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5 votes
What is the p(4,5) on two consecutive rolls of a number cube

User Teimurjan
by
6.1k points

2 Answers

4 votes
The answer to this question would be (0,0)
User Unirgy
by
6.3k points
3 votes

Answer:

p(4,5) =
(1)/(36)

Explanation:

The sample space for distribution of two consecutive throws of a dice is:

(1,1),(1,2),(1,3),(1,4),(1,5),(1,6)

(2,1),(2,2),(2,3),(2,4),(2,5),(2,6)

(3,1),(3,2),(3,3),(3,4),(3,5),(3,6)

(4,1),(4,2),(4,3),(4,4),(4,5),(4,6)

(5,1),(5,2),(5,3),(5,4),(5,5),(5,6)

(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)

There are total 36 observation.

Probability =
\frac{\text{Number of favorable outcome}}{\text{Total number of observations}}

Thus, Probability(4,5) =
(1)/(36)

User JHowzer
by
6.7k points
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