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Nullstellensatz · Answer 1 · 2018-02-06T17:51:34+0000

Assuming 0 and 100 are included in the possible choices:

There are
$\left\lfloor\frac{101}7\right\rfloor=14$ multiples of 7 between 0 and 100, so there is a
$(14)/(101)\approx0.1386$ probability of choosing a multiple of 7.

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