Question

Write the formulas of the compounds formed by Pb4+ with the following anions: NO3−, HCO3−, SO32−, PO43−. Use the given order of anions?

Answer 1

Pb(NO₃)₄
Pb(HCO₃)₄
Pb(SO₃)₂
Pb₃(PO₄)₄

Answer 2

Answer: Four ionic compounds formed will be
`Pb(NO_3)_4,Pb(HCO_3)_4,Pb(SO_3)_2\text{ and }Pb_3(PO_4)_4`

Step-by-step explanation:

Ionic compound is formed by the complete transfer of electrons from 1 atom to another atom. The cation is formed by the loss of electrons by metals and anions are formed by gain of electrons by non metals.

We are given:

One cation having formulas
`Pb^(4+)`

Four anions having formulas
`NO_3^-,HCO_3^-,SO_3^(2-)\text{ and }PO_4^(3-)`

By criss-cross method, the oxidation state of the ions gets exchanged and they form the subscripts of the other ions. This results in the formation of a neutral compound.

The four ionic compounds are:

When lead ion and nitrate ions combine, it results in the formation of
`Pb(NO_3)_4` compound. This is named as lead (IV) nitrate.

When lead ion and bicarbonate ions combine, it results in the formation of
`Pb(HCO_3)_4` compound. This is named as lead (IV) hydrogen carbonate.

When lead ion and sulfite ions combine, it results in the formation of
`Pb(SO_3)_2` compound. This is named as lead (IV) sulfite.

When lead ion and phosphate ions combine, it results in the formation of
`Pb_3(PO_4)_4` compound. This is named as lead (IV) phosphate.